\(\int (f+g x)^2 \log (c (d+e x^n)^p) \, dx\) [213]

Optimal result

Integrand size = 20, antiderivative size = 181 \[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=-\frac {e f^2 n p x^{1+n} \operatorname {Hypergeometric2F1}\left (1,1+\frac {1}{n},2+\frac {1}{n},-\frac {e x^n}{d}\right )}{d (1+n)}-\frac {e f g n p x^{2+n} \operatorname {Hypergeometric2F1}\left (1,\frac {2+n}{n},2 \left (1+\frac {1}{n}\right ),-\frac {e x^n}{d}\right )}{d (2+n)}-\frac {e g^2 n p x^{3+n} \operatorname {Hypergeometric2F1}\left (1,\frac {3+n}{n},2+\frac {3}{n},-\frac {e x^n}{d}\right )}{3 d (3+n)}-\frac {f^3 p \log \left (d+e x^n\right )}{3 g}+\frac {(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g} \]

[Out]

-e*f^2*n*p*x^(1+n)*hypergeom([1, 1+1/n],[2+1/n],-e*x^n/d)/d/(1+n)-e*f*g*n*p*x^(2+n)*hypergeom([1, (2+n)/n],[2+
2/n],-e*x^n/d)/d/(2+n)-1/3*e*g^2*n*p*x^(3+n)*hypergeom([1, (3+n)/n],[2+3/n],-e*x^n/d)/d/(3+n)-1/3*f^3*p*ln(d+e
*x^n)/g+1/3*(g*x+f)^3*ln(c*(d+e*x^n)^p)/g

Rubi [A] (verified)

Time = 0.12 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2513, 1858, 266, 371} \[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=\frac {(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac {f^3 p \log \left (d+e x^n\right )}{3 g}-\frac {e f^2 n p x^{n+1} \operatorname {Hypergeometric2F1}\left (1,1+\frac {1}{n},2+\frac {1}{n},-\frac {e x^n}{d}\right )}{d (n+1)}-\frac {e f g n p x^{n+2} \operatorname {Hypergeometric2F1}\left (1,\frac {n+2}{n},2 \left (1+\frac {1}{n}\right ),-\frac {e x^n}{d}\right )}{d (n+2)}-\frac {e g^2 n p x^{n+3} \operatorname {Hypergeometric2F1}\left (1,\frac {n+3}{n},2+\frac {3}{n},-\frac {e x^n}{d}\right )}{3 d (n+3)} \]

[In]

Int[(f + g*x)^2*Log[c*(d + e*x^n)^p],x]

[Out]

-((e*f^2*n*p*x^(1 + n)*Hypergeometric2F1[1, 1 + n^(-1), 2 + n^(-1), -((e*x^n)/d)])/(d*(1 + n))) - (e*f*g*n*p*x
^(2 + n)*Hypergeometric2F1[1, (2 + n)/n, 2*(1 + n^(-1)), -((e*x^n)/d)])/(d*(2 + n)) - (e*g^2*n*p*x^(3 + n)*Hyp
ergeometric2F1[1, (3 + n)/n, 2 + 3/n, -((e*x^n)/d)])/(3*d*(3 + n)) - (f^3*p*Log[d + e*x^n])/(3*g) + ((f + g*x)
^3*Log[c*(d + e*x^n)^p])/(3*g)

Rule 266

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 371

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^p*((c*x)^(m + 1)/(c*(m + 1)))*Hyperg
eometric2F1[-p, (m + 1)/n, (m + 1)/n + 1, (-b)*(x^n/a)], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 1858

Int[(Pq_)*((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*Pq*(a +
b*x^n)^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] && (PolyQ[Pq, x] || PolyQ[Pq, x^n]) &&  !IGtQ[m, 0]

Rule 2513

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.) + (g_.)*(x_))^(r_.), x_Symbol] :> Simp[(f
+ g*x)^(r + 1)*((a + b*Log[c*(d + e*x^n)^p])/(g*(r + 1))), x] - Dist[b*e*n*(p/(g*(r + 1))), Int[x^(n - 1)*((f
+ g*x)^(r + 1)/(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, r}, x] && (IGtQ[r, 0] || RationalQ[n
]) && NeQ[r, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac {(e n p) \int \frac {x^{-1+n} (f+g x)^3}{d+e x^n} \, dx}{3 g} \\ & = \frac {(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac {(e n p) \int \left (\frac {f^3 x^{-1+n}}{d+e x^n}+\frac {3 f^2 g x^n}{d+e x^n}+\frac {3 f g^2 x^{1+n}}{d+e x^n}+\frac {g^3 x^{2+n}}{d+e x^n}\right ) \, dx}{3 g} \\ & = \frac {(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\left (e f^2 n p\right ) \int \frac {x^n}{d+e x^n} \, dx-\frac {\left (e f^3 n p\right ) \int \frac {x^{-1+n}}{d+e x^n} \, dx}{3 g}-(e f g n p) \int \frac {x^{1+n}}{d+e x^n} \, dx-\frac {1}{3} \left (e g^2 n p\right ) \int \frac {x^{2+n}}{d+e x^n} \, dx \\ & = -\frac {e f^2 n p x^{1+n} \, _2F_1\left (1,1+\frac {1}{n};2+\frac {1}{n};-\frac {e x^n}{d}\right )}{d (1+n)}-\frac {e f g n p x^{2+n} \, _2F_1\left (1,\frac {2+n}{n};2 \left (1+\frac {1}{n}\right );-\frac {e x^n}{d}\right )}{d (2+n)}-\frac {e g^2 n p x^{3+n} \, _2F_1\left (1,\frac {3+n}{n};2+\frac {3}{n};-\frac {e x^n}{d}\right )}{3 d (3+n)}-\frac {f^3 p \log \left (d+e x^n\right )}{3 g}+\frac {(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.16 (sec) , antiderivative size = 178, normalized size of antiderivative = 0.98 \[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=\frac {-e n p \left (\frac {3 f^2 g x^{1+n} \operatorname {Hypergeometric2F1}\left (1,1+\frac {1}{n},2+\frac {1}{n},-\frac {e x^n}{d}\right )}{d (1+n)}+\frac {3 f g^2 x^{2+n} \operatorname {Hypergeometric2F1}\left (1,\frac {2+n}{n},2 \left (1+\frac {1}{n}\right ),-\frac {e x^n}{d}\right )}{d (2+n)}+\frac {g^3 x^{3+n} \operatorname {Hypergeometric2F1}\left (1,\frac {3+n}{n},2+\frac {3}{n},-\frac {e x^n}{d}\right )}{d (3+n)}+\frac {f^3 \log \left (d+e x^n\right )}{e n}\right )+(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g} \]

[In]

Integrate[(f + g*x)^2*Log[c*(d + e*x^n)^p],x]

[Out]

(-(e*n*p*((3*f^2*g*x^(1 + n)*Hypergeometric2F1[1, 1 + n^(-1), 2 + n^(-1), -((e*x^n)/d)])/(d*(1 + n)) + (3*f*g^
2*x^(2 + n)*Hypergeometric2F1[1, (2 + n)/n, 2*(1 + n^(-1)), -((e*x^n)/d)])/(d*(2 + n)) + (g^3*x^(3 + n)*Hyperg
eometric2F1[1, (3 + n)/n, 2 + 3/n, -((e*x^n)/d)])/(d*(3 + n)) + (f^3*Log[d + e*x^n])/(e*n))) + (f + g*x)^3*Log
[c*(d + e*x^n)^p])/(3*g)

Maple [F]

\[\int \left (g x +f \right )^{2} \ln \left (c \left (d +e \,x^{n}\right )^{p}\right )d x\]

[In]

int((g*x+f)^2*ln(c*(d+e*x^n)^p),x)

[Out]

int((g*x+f)^2*ln(c*(d+e*x^n)^p),x)

Fricas [F]

\[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=\int { {\left (g x + f\right )}^{2} \log \left ({\left (e x^{n} + d\right )}^{p} c\right ) \,d x } \]

[In]

integrate((g*x+f)^2*log(c*(d+e*x^n)^p),x, algorithm="fricas")

[Out]

integral((g^2*x^2 + 2*f*g*x + f^2)*log((e*x^n + d)^p*c), x)

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 8.09 (sec) , antiderivative size = 360, normalized size of antiderivative = 1.99 \[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=- \frac {d^{-2 - \frac {3}{n}} d^{1 + \frac {3}{n}} e g^{2} p x^{n + 3} \Phi \left (\frac {e x^{n} e^{i \pi }}{d}, 1, 1 + \frac {3}{n}\right ) \Gamma \left (1 + \frac {3}{n}\right )}{3 \Gamma \left (2 + \frac {3}{n}\right )} - \frac {d^{-2 - \frac {3}{n}} d^{1 + \frac {3}{n}} e g^{2} p x^{n + 3} \Phi \left (\frac {e x^{n} e^{i \pi }}{d}, 1, 1 + \frac {3}{n}\right ) \Gamma \left (1 + \frac {3}{n}\right )}{n \Gamma \left (2 + \frac {3}{n}\right )} - \frac {d^{-2 - \frac {2}{n}} d^{1 + \frac {2}{n}} e f g p x^{n + 2} \Phi \left (\frac {e x^{n} e^{i \pi }}{d}, 1, 1 + \frac {2}{n}\right ) \Gamma \left (1 + \frac {2}{n}\right )}{\Gamma \left (2 + \frac {2}{n}\right )} - \frac {2 d^{-2 - \frac {2}{n}} d^{1 + \frac {2}{n}} e f g p x^{n + 2} \Phi \left (\frac {e x^{n} e^{i \pi }}{d}, 1, 1 + \frac {2}{n}\right ) \Gamma \left (1 + \frac {2}{n}\right )}{n \Gamma \left (2 + \frac {2}{n}\right )} + f^{2} x \log {\left (c \left (d + e x^{n}\right )^{p} \right )} + f g x^{2} \log {\left (c \left (d + e x^{n}\right )^{p} \right )} + \frac {g^{2} x^{3} \log {\left (c \left (d + e x^{n}\right )^{p} \right )}}{3} + \frac {d^{- \frac {1}{n}} d^{1 + \frac {1}{n}} e e^{\frac {1}{n}} e^{-1 - \frac {1}{n}} f^{2} p x \Phi \left (\frac {d x^{- n} e^{i \pi }}{e}, 1, \frac {e^{i \pi }}{n}\right ) \Gamma \left (\frac {1}{n}\right )}{d n \Gamma \left (1 + \frac {1}{n}\right )} \]

[In]

integrate((g*x+f)**2*ln(c*(d+e*x**n)**p),x)

[Out]

-d**(-2 - 3/n)*d**(1 + 3/n)*e*g**2*p*x**(n + 3)*lerchphi(e*x**n*exp_polar(I*pi)/d, 1, 1 + 3/n)*gamma(1 + 3/n)/
(3*gamma(2 + 3/n)) - d**(-2 - 3/n)*d**(1 + 3/n)*e*g**2*p*x**(n + 3)*lerchphi(e*x**n*exp_polar(I*pi)/d, 1, 1 +
3/n)*gamma(1 + 3/n)/(n*gamma(2 + 3/n)) - d**(-2 - 2/n)*d**(1 + 2/n)*e*f*g*p*x**(n + 2)*lerchphi(e*x**n*exp_pol
ar(I*pi)/d, 1, 1 + 2/n)*gamma(1 + 2/n)/gamma(2 + 2/n) - 2*d**(-2 - 2/n)*d**(1 + 2/n)*e*f*g*p*x**(n + 2)*lerchp
hi(e*x**n*exp_polar(I*pi)/d, 1, 1 + 2/n)*gamma(1 + 2/n)/(n*gamma(2 + 2/n)) + f**2*x*log(c*(d + e*x**n)**p) + f
*g*x**2*log(c*(d + e*x**n)**p) + g**2*x**3*log(c*(d + e*x**n)**p)/3 + d**(1 + 1/n)*e*e**(1/n)*e**(-1 - 1/n)*f*
*2*p*x*lerchphi(d*exp_polar(I*pi)/(e*x**n), 1, exp_polar(I*pi)/n)*gamma(1/n)/(d*d**(1/n)*n*gamma(1 + 1/n))

Maxima [F]

\[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=\int { {\left (g x + f\right )}^{2} \log \left ({\left (e x^{n} + d\right )}^{p} c\right ) \,d x } \]

[In]

integrate((g*x+f)^2*log(c*(d+e*x^n)^p),x, algorithm="maxima")

[Out]

-1/9*(g^2*n*p - 3*g^2*log(c))*x^3 - 1/2*(f*g*n*p - 2*f*g*log(c))*x^2 - (f^2*n*p - f^2*log(c))*x + 1/3*(g^2*x^3
+ 3*f*g*x^2 + 3*f^2*x)*log((e*x^n + d)^p) + integrate(1/3*(d*g^2*n*p*x^2 + 3*d*f*g*n*p*x + 3*d*f^2*n*p)/(e*x^
n + d), x)

Giac [F]

\[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=\int { {\left (g x + f\right )}^{2} \log \left ({\left (e x^{n} + d\right )}^{p} c\right ) \,d x } \]

[In]

integrate((g*x+f)^2*log(c*(d+e*x^n)^p),x, algorithm="giac")

[Out]

integrate((g*x + f)^2*log((e*x^n + d)^p*c), x)

Mupad [F(-1)]

Timed out. \[ \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx=\int \ln \left (c\,{\left (d+e\,x^n\right )}^p\right )\,{\left (f+g\,x\right )}^2 \,d x \]

[In]

int(log(c*(d + e*x^n)^p)*(f + g*x)^2,x)

[Out]

int(log(c*(d + e*x^n)^p)*(f + g*x)^2, x)